48x^2-438x-420=0

Solution for 48x^2-438x-420=0 equation:

48x^2-438x-420=0

a = 48; b = -438; c = -420;
Δ = b2-4ac
Δ = -4382-4·48·(-420)
Δ = 272484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{272484}=522$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-438)-522}{2*48}=\frac{-84}{96}
=-7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-438)+522}{2*48}=\frac{960}{96}
=10
$